Hi Vadim,

Hope you are trying to register your application after the server
startAndWaitUp. Do you mind sharing your Main function code over here ?

A working sample would be something like this:

public static void main( String[] args ) throws Exception
{
// TODO Change to correct URI
String uri = "tcp://10.89.31.153:9000";

RemoteInAndOut_JavaServer server =
InAndOut_JavaHelper.newServer( uri, null,
new MainInAndOut_JavaClient() );

// Connect to the service
server._startAndWaitUp( 4000 );

// TODO Insert Your Code Here
String key = server.registerApplication("InAndOut_Java",
"Default", "Administrator", "metreos");
System.out.println("Application Successfully registered
with key:"+key);
System.out.println("Press Any key to exit from the
application");
System.in.read();
// Disconnect from the service
server._stopAndWaitDown( 4000 );
}

regards,
Ram

Cisco Developer Services
http://developer.cisco.com/

-----Original Message-----
From: cuae-developers-bounces@developer.cisco.com
mailto:cuae-developers-bounces@developer.cisco.com On Behalf Of Vadim
Bruk
Sent: Wednesday, June 18, 2008 5:44 PM
To: cuae-developers@developer.cisco.com
Subject: [Cuae-developers] registering application

Hi,

After successful connecting I call registerApplication method and it
blocks there.
I do the method call with valid credentials and partition parameter
"Default". I've traced the method call down - it blocks somewhere after
calling of _end_registerApplication method of RemoteEtchBridgeServer
class.
What could be the problem?

Thank you,
Vadim.
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Cuae-developers@developer.cisco.com

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Hi Vadim,

It looks like after registration your app terminated as well... since
you called the server stop command...

Could you add these before server._stop...

System.out.println("Application Successfully registered
with key:"+ regRes);
System.out.println("Press Any key to exit from the
application");
System.in.read();
// Disconnect from the service

Let me know how this goes.

regards,
Ram

Cisco Developer Services
http://developer.cisco.com/

-----Original Message-----
From: cuae-developers-bounces@developer.cisco.com
mailto:cuae-developers-bounces@developer.cisco.com On Behalf Of Vadim
Bruk
Sent: Thursday, June 19, 2008 10:54 AM
To: cuae-developers@developer.cisco.com
Subject: Re: [Cuae-developers] registering application

Here is my main method:
public static void main( String[] args ) throws Exception
{
// TODO Change to correct URI
RemotejtapitestServer server = null;
String uri = "tcp://10.11.3.23:9000";// + String.valueOf(i);
System.out.println("Connecting to: " + uri);
server = jtapitestHelper.newServer( uri, null,
new MainjtapitestClient() );

// Connect to the service
server._startAndWaitUp( 4000 );

String regRes = server.registerApplication("jtapiTest",
"Default", "administrator", "Password?");

// Disconnect from the service
server._stopAndWaitDown( 4000 );
}

Please note that it never returns from registerApplication method.
_______________________________________________
Cuae-developers mailing list
Cuae-developers@developer.cisco.com

_______________________________________________
Cuae-developers mailing list
Cuae-developers@developer.cisco.com