Event Center - How could I get Attendees Url 、Panelists Url via XML API ? http://developer.cisco.com/c/message_boards/find_thread?p_l_id=&threadId=8024006 2013-05-19T22:53:33Z 2013-05-19T22:53:33Z Nathan Morrow http://developer.cisco.com/c/message_boards/find_message?p_l_id=&messageId=8043772 2012-10-25T19:02:53Z 2012-10-25T19:02:53Z

GethosturlMeeting and GetjoinurlMeeting will return entry links for host and attendees/panelists. You must provide name, email address, password if the event has a join password, and enrolment id if the even requires enrollment id. If all the required values are provided, the join link will directly launch the attendee/panelist in to the Event. Both of these commands are generating a URL API join command, so you could skip the XML request and build the URL directly if you chose to do so.

Nathan Morrow 2012-10-25T19:02:53Z Claire Huang http://developer.cisco.com/c/message_boards/find_message?p_l_id=&messageId=8024005 2012-10-25T01:47:52Z 2012-10-25T01:47:32Z

Hi, I am using CreateEvent API to schedule the event. How could I get [color=#0000ff]Attendees Url [/color]、[color=#0000ff]Panelists Url[/color] and [color=#0000ff]Host Url[/color] [b][color=#ff0000]via XML API  [/color][/b]to enter a session directly (no name, ID or password required). Thanks In advance. BR, Claire

Claire Huang 2012-10-25T01:47:32Z